How do you find $abs( -3-6i )$ ?

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Answer 1 · 2016-05-23T14:00:55

$|-3-6i|=3sqrt5$

Absolute value of a complex number $a+ib$ is denoted as $|a+ib|$

and is given by $sqrt(a^2+b^2)$

Hence absolute value $|-3-6i|$ is

$sqrt(3^2+6^2)=sqrt(9+36)=sqrt45=3sqrt5$

How do you find abs( -3-6i )abs( -3-6i )?