How do you find abs( 3+9i )? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Konstantinos Michailidis May 1, 2016 It is known for a given comlex number its magnitude is abs(a+bi)=sqrt(a^2+b^2) Hence abs(3+9i)=sqrt(3^2+9^2)=sqrt90=3sqrt10 Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number 3+4i in the complex plane? How do I graph the complex number 2-3i in the complex plane? How do I graph the complex number -4+2i in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number 4i in the complex number plane? How do I use graphing in the complex plane to add 2+4i and 5+3i? How do I use graphing in the complex plane to subtract 3+4i from -2+2i? See all questions in Complex Number Plane Impact of this question 2956 views around the world You can reuse this answer Creative Commons License