How do you find $abs(4 - 3i )$ ?

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Answer 1 · 2016-03-25T09:32:57

$|4-3i|=5$

Finding $|4-3i|$ means finding the modulus of complex number $4-3i$ .

As modulus of a complex number $a+bi$ is given by $sqrt(a^2+b^2)$

$|4-3i|=sqrt(4^2+(-3)^2)=sqrt(16+9)=sqrt25=5$

How do you find abs(4 - 3i )abs(4 - 3i )?