How do you find $abs(4 + 5i)$ ?

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Answer 1 · 2016-04-09T02:03:24

$|4+5i| = sqrt(41)$

Given a complex number $a+bi$ , we define the modulus of the number, denoted $|a+bi|$ as

$|a+bi| = sqrt(a^2+b^2)$

In this case, that gives us

$|4+5i| = sqrt(4^2+5^2) = sqrt(41)$

How do you find abs(4 + 5i)abs(4 + 5i)?