Question

How do you find `abs( 4(sqrt3) - 4i)`?

Answer 1

The magnitude of a complex number is

`abs(a+bi)=sqrt(a^2+b^2)`

Hence

#abs(4sqrt3-4i)=sqrt((4sqrt3)^2+4^2)=sqrt(4^2(3+1))= 4*sqrt4=4*2=8#