Question

How do you find `abs( 5+12i )`?

Answer 1

The answer is `=13`

Explanation:

The modulus of a complex number

`z=a+ib`

is

`|z|= |a+ib|=sqrt(a^2+b^2)`

Here, we have

`z=5+12i`

Therefore,

`|z|=sqrt(5^2+12^2)=sqrt(25+144)=sqrt169=13`