How do you find $abs(5-2i)$ ?

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Answer 1 · 2016-07-17T06:08:13

$|5-2i| = sqrt(29)$

The modulus of a complex number $a+bi$ , denoted as $|a+bi|$ , is given by

$|a+bi| = sqrt(a^2+b^2)$

and represents the distance of that number from the origin on the complex plane.

For our given number, then, we have

$|5-2i| = sqrt(5^2+(-2)^2)$

$=sqrt(25+4)$

$=sqrt(29)$

How do you find abs(5-2i)abs(5-2i)?