How do you find $abs(7-9i)$ ?

Question

3591 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-23T14:02:18

$|7-9i|=sqrt130$

Absolute value of a complex number $a+ib$ is denoted as $|a+ib|$

and is given by $sqrt(a^2+b^2)$

Hence absolute value $|7-9i|$ is

$sqrt(7^2+9^2)=sqrt(49+81)=sqrt130$

How do you find abs(7-9i)abs(7-9i)?