How do you find $abs(-8-4i)$ ?

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Answer 1 · 2016-08-18T11:05:46

$|-8-4i|=4sqrt5~=8.9444$ .

For, $z=x+iy in CC, |z|=sqrt(x^2+y^2)$ .

Hence, $|-8-4i|=sqrt((-8)^2+(-4)^2)=sqrt(64+16)=sqrt80=sqrt(4^2*5)=4sqrt5$ .

Taking, $sqrt5~=2.2361$ , Reqd. Value $~=4*2.2361=8.9444$ .

How do you find abs(-8-4i)abs(-8-4i)?