How do you find $abs(i^2)$ ?

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Answer 1 · 2016-04-16T19:32:11

$abs(i^2) = 1$

$i$ is the square root of $-1$ , or

$i = sqrt(-1)$ .

Therefore,

$i^2 = -1$ ,

simply by the definition of a square root.

Ultimate value ( $abs$ ) can be thought of as the distance of a certain number from $0$ , always as a positive number, so

$abs(-1) = 1$

and, by extension,

$abs(i^2) = 1$

How do you find abs(i^2)abs(i^2)?