How do you find $cot (- 180)$ $cot(-180)$ ?

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Answer 1 · 2015-02-03T09:31:20

The answer is: it does not exists.

The function $y = cot x$ $y=cotx$ would be writtend in this form:

$cot x = \frac{1}{tan x} = \frac{1}{\frac{sin x}{cos x}} = \frac{cos x}{sin x}$ $cotx=1/tanx=1/(sinx/cosx)=cosx/sinx$ .

So:

$cot(-180°)=cos(-180°)/sin(-180°)$ .

$cos(-180°)=-1$ ,
$sin(-180°)=0$ .

$cot(-180°)=1/0$ that does not exists (or we can say that the function $rarr+-oo$ ).

How do you find cot(-180)cot(−180)cot(-180)?