How do you find domain and range for $f(x) = 2 / (1 - x²)$ ?

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Answer 1 · 2015-09-25T04:29:28

Refer to explanation

The domain is $R-{-1,1}$ and the range is

$f(x)=2/(1-x^2)=>1-x^2=2/(f(x))=>1-2/f(x)=x^2>=0=> f(x)*(f(x)-2)>=0$

hence the range is $R(f)=(-oo,0)U[2,+oo)$

How do you find domain and range for f(x) = 2 / (1 - x²)f(x) = 2 / (1 - x²)?