How do you find domain and range for $f (x) = \frac{x - 6}{x + 1}$ $f(x) = (x-6)/(x+1)$ ?

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Answer 1 · 2018-04-30T04:51:01

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$f (x) = \frac{x - 6}{x + 1}$ $f(x)=(x-6)/(x+1)$

$f (x) = \frac{(x + 1) - 7}{x + 1}$ $f(x)=((x+1)-7)/(x+1)$

$f (x) = 1 - \frac{7}{x + 1}$ $f(x)=1-7/(x+1)$

Therefore, the domain is all reals except when $x = - 1$ $x=-1$ and range is all reals except when $y = 1$ $y=1$

How do you find domain and range for f(x)=x−6x+1f(x) = (x-6)/(x+1)?