How do you find domain and range for $y = \sqrt{x - 2}$ $y=sqrt(x- 2)$ ?

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Answer 1 · 2015-10-07T06:11:01

The domain is $x \geq 2$ $x>=2$ or $D (f) = [2, + \infty)$ $D(f)=[2,+oo)$ and the range is

$y = \sqrt{x - 2} \geq 0 \Rightarrow y \geq 0$ $y=sqrt(x-2)>=0=>y>=0$ or $R (f) = [0, + \infty)$ $R(f)=[0,+oo)$

How do you find domain and range for y=√x−2y=sqrt(x- 2)?