How do you find five ordered pairs of $y^{2} = x$ $y^2 = x$ ?

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Answer 1 · 2018-07-18T23:31:52

$(0, 0), (1, - 1), (1, 1), (4, 2), (4, - 2)$ $(0, 0), (1, -1), (1, 1), (4, 2), (4, -2)$

Given: $y^{2} = x$ $y^2 = x$

Rewrite the equation in $y =$ $y =$ form by square rooting both sides:

$y = \pm \sqrt{x}$ $y = +- sqrt(x)$

Since $x$ $x$ is the independent variable, we can select values that we want to use to calculate $y$ $y$ :

How do you find five ordered pairs of y^2 = xy2=xy^2 = x?