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How do you find $sin ({sin}^{- 1} x + {cos}^{- 1} y)$ $sin(sin^-1x+cos^-1y)$ ?

1 Answer

Mar 6, 2018

sin (x + y)

Explanation:

$sin ({sin}^{- 1} x + {cos}^{- 1} y)$ $sin (sin ^-1 x + cos ^-1 y)$ -->

sin (arcsin x + arccos y) = sin (x + y) =
= sin x.cos y + sin y.cos x.

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