How do you find slope of (1,-1); (-2,-6)?

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Answer 1 · 2015-04-07T08:38:44

#Slope# = $\frac{R i s e}{R u n}$ $(Rise)/(Run)$
The $R i s e$ $Rise$ is the Difference of the Y coordinates of any two points on the line
And the $R u n$ $Run$ is the Difference of the X coordinates of those two points
If the coordinates of the points are $(x_{1}, y_{1}) and (x_{2}, y_{2})$ $(x_1,y_1) and (x_2,y_2)$ , then $S l o p e = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $Slope = (y_2-y_1)/(x_2-x_1)$
Here, the coordinates are $(1, - 1)$ $(1,-1)$ and $(- 2, - 6)$ $(-2,-6)$

$S l o p e = \frac{- 6 - (- 1)}{- 2 - 1} = \frac{- 6 + 1}{- 3} = \frac{- 5}{- 3} = \frac{5}{3}$ $Slope = (-6-(-1))/(-2-1)=(-6+1)/-3=(-5)/-3=5/3$

The slope of the line passing through points (1,-1) and (-2,-6) is $\frac{5}{3}$ $5/3$

The graph of the line will look like this:
graph{y=(5x/3)-(8/3) [-10, 10, -5, 5]}