How do you find the 6 trig functions of 120 degrees?

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Answer 1 · 2015-07-10T10:59:46

$sin120=sqrt(3)/2$

$cos120=-1/2$

$tan120=-sqrt(3)$

$ctg120=-sqrt(3)/3$

$sec120=-2$

$csec120=(2sqrt(3))/3$

To calculate $sin120$ and $cos120$ you can use the reduction formula, which says, that

$sin(180-x)=sinx$ and $cos(180-x)=-cosx$

Rest of the functions can be calculated as:

$tanx=sinx/cosx$

$ctgx=1/tanx$

$secx=1/cosx$

$csecx=1/sinx$