How do you find the 6 trig functions of 330 degrees?

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Answer 1 · 2015-05-07T16:02:53

Trig unit circle gives:

$sin (330) = sin (360 - 30) = -sin 30 = -1/2$ (trig table)

$cos (330) = cos (360 - 30) = cos 30 = (sqr3)/2$ (trig table)

$tan (330) = (-1/2)(2/(sqr3)) = -1/(sqr3) = -(sqr3)/3$

$cot (330) = -sqr3$

$sec (330) = 2/(sqr3) = (2.sqr3)/3$

$csc (330) = -2$