How do you find the 6 trigonometric functions for 225 degrees?

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How do you find the 6 trigonometric functions for 225 degrees?

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Answer 1 · 2015-08-23T07:04:14

Find 6 trig functions of 225 deg

Explanation:

$sin 225 = sin (45 + 180) = - sin 45 = - \frac{\sqrt{2}}{2}$ $sin 225 = sin (45 + 180) = - sin 45 = -sqrt2/2$
$cos 225 = cos (45 + 180) = - cos 45 = - \frac{\sqrt{2}}{2}$ $cos 225 = cos (45 + 180) = - cos 45 = -sqrt2/2$
$tan 225 = \frac{sin 225}{cos 225} = 1$ $tan 225 = sin 225/cos 225 = 1$
$cot 225 = \frac{1}{tan 225} = 1$ $cot 225 = 1/tan 225 = 1$
$sec 225 = \frac{1}{cos 225} = - \sqrt{2}$ $sec 225 = 1/cos 225 = -sqrt2$
$csc 225 = \frac{1}{sin 225} = - \sqrt{2}$ $csc 225 = 1/sin 225 = - sqrt2$

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How do you find the 6 trigonometric functions for 225 degrees?

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