How do you find the 6 trigonometric functions for x =3π/4?

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How do you find the 6 trigonometric functions for x =3π/4?

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Answer 1 · 2015-08-18T15:01:39

sin $(\frac{3 π}{4})$ $((3pi)/4)$ = $\frac{1}{\sqrt{2}}$ $1/sqrt2$
cos $(\frac{3 π}{4})$ $((3pi)/4)$ = $- \frac{1}{\sqrt{2}}$ $- 1/sqrt2$ . Rest can be worked out using these values.

Explanation:

To begin with, $\frac{3 π}{4} e q u a l s (π - \frac{π}{4})$ $(3pi)/4equals (pi- pi/4)$ . Hence,

sin $(\frac{3 π}{4}) = sin (π - \frac{π}{4}) = sin (\frac{π}{4}) = \frac{1}{\sqrt{2}}$ $((3pi)/4)= sin (pi-pi/4)= sin((pi)/4)= 1/sqrt2$ . Like wise,

cos $(\frac{3 π}{4}) = cos (π - \frac{π}{4}) = - cos (\frac{π}{4}) = - \frac{1}{\sqrt{2}}$ $((3pi)/4)= cos(pi-pi/4)= - cos(pi/4)= -1/sqrt2$ .

Other trignometric functions can now be easily worked out, $tan (\frac{3 π}{4}) = - 1, cot (\frac{3 π}{4}) = - 1, sec (\frac{3 π}{4}) = - \sqrt{2}, csc (\frac{3 π}{4}) = \sqrt{2}$ $tan((3pi)/4)= -1, cot((3pi)/4)=-1, sec((3pi)/4)=-sqrt2, csc((3pi)/4)= sqrt2$

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How do you find the 6 trigonometric functions for x =3π/4?

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