How do you find the absolute value of $4-8i$ ?

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Answer 1 · 2016-07-12T10:10:42

$|4-8i|=sqrt{4^2+(-8)^2}=sqrt(16+64)=sqrt80=4sqrt5.$

Taking, $sqrt5~=2.236, |z|~=4xx2.236=8.944$

Absolute Value or Modulus $|z|$ of a Complex No. $z=x+iy$ is defined by,

$|z|=sqrt(x^2+y^2).$

$|4-8i|=sqrt{4^2+(-8)^2}=sqrt(16+64)=sqrt80=4sqrt5$

Taking, $sqrt5~=2.236, |z|~=4xx2.236=8.944$

How do you find the absolute value of 4-8i4-8i?