How do you find the absolute value of $sqrt11+isqrt5$ ?

Question

1634 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-21T22:12:04

$|sqrt11+isqrt5|=4$

The absolute value of a complex number $a+bi$ is written as $|a+bi|$ and its value is $sqrt(a^2+b^2)$ .

Hence, absolute value of $sqrt11+isqrt5$ is

$|sqrt11+isqrt5|$

= $sqrt((sqrt11)^2+(sqrt5)^2)$

= $sqrt(11+5)$

= $sqrt16$

= $4$ .

How do you find the absolute value of sqrt11+isqrt5sqrt11+isqrt5?