How do you find the area of the rectangle with vertices A(-3,0), B(-2,-1), C(1,2), D(0,3)?

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Answer 1 · 2016-02-06T13:21:29

Area#=6# square units

Area #=(1/2)*(x_a*y_b+x_b*y_c+x_c*y_d+x_d*y_a-x_b*y_a-x_c*y_b-x_d*y_c-x_a*y_d)#

Area #=(1/2)*(-3(-1)+(-2)(2)+(1)(3)+0(0)-[0(-2)+(-1)(1)+2(0)+(3(-3])#

Area #=(1/2)*(6-4-(-10))#

Area#=6#

Have a nice day !! from the Philippines...

Answer 2 · 2016-02-06T13:41:46

#6# sq. units

#"Area"_square = "Length" xx "Width"#

Using #|AB|# as the "Width"
and #|AD|# as the "Length"

#|AB| = sqrt((-3-(-2))^2+(0-(-1))^2)=sqrt(2)#
#|AD|=sqrt((-3-0)^2+(0-3)^2)=3sqrt(2)#

#"Area"_square = 3sqrt(2)xxsqrt(2)=6#