Question

How do you find the axis of symmetry, and the maximum or minimum value of the function `y=3x^{2}+12x-2`?

Answer 1

Min at vertex (-2, -14)

Explanation:

x-coordinate of vertex, or axis of symmetry:
`x = -b/(2a) = -12/6 = - 2`
y-coordinate of vertex:
y(-2) = 3(4) - 12(2) - 2 = -14
Since a > 0, the parabola opens upward, there is min at vertex.
Min at vertex (-2, -14)