How do you find the axis of symmetry, and the maximum or minimum value of the function $y = 2 {(x - 2)}^{2} - 3$ $y=2(x-2)^2-3$ ?

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Answer 1 · 2017-05-30T16:36:23

Minimum

Vertex $\to (x, y) = (+ 2, - 3)$ $->(x,y)=(+2,-3)$

Axis of symmetry is $x = + 2$ $x=+2$

If you multiply out the brackets the highest order term is $+ 2 x^{2}$ $+2x^2$

As this is positive the graph is of form $\cup$ $uu$ thus we have a minimum/

Consider $y = 2 {(x - 2)}^{2} - 3$ $color(green)(y=2(xcolor(red)(-2))^2color(red)(-3)$

Then Vertex $\to (x, y) = (+ 2, - 3)$ $->(x,y)=(color(red)(+2,-3))$

So Axis of symmetry is $x = + 2$ $x=+2$

Tony B

How do you find the axis of symmetry, and the maximum or minimum value of the function y=2(x-2)^2-3y=2(x−2)2−3y=2(x-2)^2-3?