How do you find the circumference and area of the circle whose equation is $x^{2} + y^{2} = 36$ $x^2+y^2=36$ ?

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How do you find the circumference and area of the circle whose equation is $x^{2} + y^{2} = 36$ $x^2+y^2=36$ ?

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Answer 1 · 2016-01-27T02:37:04

Circumference = $12 π$ $12 pi$ .
Area = $36 π$ $36 pi$ .

Explanation:

The equation of a circle centred in the origin having radius r is $x^{2} + y^{2} = r^{2}$ $x^2 + y^2 = r^2$ . Comparing with the equation of the given circle, we get $r^{2} = 36 \Rightarrow r = 6$ $r^2 = 36 => r = 6$ . (Since $r > 0$ $r > 0$ .)

Note that all we need to calculate the area and circumference of a circle is the radius. Now we can use the formulae known to calculate the required values.

Circumference = $2 π r = 2 π \cdot 6 = 12 π$ $2 pi r = 2 pi * 6 = 12 pi$ .
Area = $π r^{2} = 36 π$ $pi r^2 = 36 pi$ .

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How do you find the circumference and area of the circle whose equation is $x^{2} + y^{2} = 36$ $x^2+y^2=36$ ?

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Explanation:

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How do you find the circumference and area of the circle whose equation is $x^{2} + y^{2} = 36$ $x^2+y^2=36$ ?