How do you find the critical points to graph $f (x) = 4 sin (x - \frac{π}{2}) + 1$ $f(x) = 4 sin(x - pi/2 ) + 1$ ?

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Answer 1 · 2016-02-28T18:55:00

0 and 2 $π$ $pi$ in the interval $(0, 2 π]$ $(0, 2pi]$

$f' (x)= 4 cos (x-pi/2)$
At critical points f'(x)=0, that gives $cos(x-pi/2)=0$

$x-pi/2 =pi/2 , (3pi)/2$
$x= pi , 2pi$ in the interval $(0,2pi]$

How do you find the critical points to graph f(x) = 4 sin(x - pi/2 ) + 1f(x)=4sin(x−π2)+1 f(x) = 4 sin(x - pi/2 ) + 1?