Question

How do you find the derivative of `1/(x^3-x^2)`?

Answer 1

`(2-3x)/(x^3(x-1)^2)`

Explanation:

`f'(x)=-(3x^2-2x)/(x^3-x^2)^2`

`=-(cancelx(3x-2))/(x^(cancel4^3)(x-1)^2)`

`=(2-3x)/(x^3(x-1)^2)`