How do you find the derivative of (6x^5 + 3x^3 +x)/x^2 6x5+3x3+xx2?

1 Answer
Oct 24, 2015

d/dx(6x^5+3x^3+x)/x^2=((x^2)(30x^4+9x^2+1)-2x(6x^5+3x^3+x))/x^4ddx6x5+3x3+xx2=(x2)(30x4+9x2+1)2x(6x5+3x3+x)x4

Explanation:

We may use the quotient rule to differentiate this function to obtain :

d/dx(6x^5+3x^3+x)/x^2=((x^2)(30x^4+9x^2+1)-2x(6x^5+3x^3+x))/x^4ddx6x5+3x3+xx2=(x2)(30x4+9x2+1)2x(6x5+3x3+x)x4