Question

How do you find the derivative of `f(t) = t^2sin t`?

Answer 1

`=> f'(t) = 2tsint + t^2 cost`

Explanation:

For this problem we must use a rule called the product rule:

`d/(dt) ( h(t) g(t) ) = h'(t)g(t) + h(t)g'(t)`

Where `h'(t) = d/(dt) (h(t) )` if your not aware

So in this `h(t) = t^2` and `g(t) = sint`

`=> f'(t) = (d/(dt) (t^2) * sint) + (t^2* d/(dt) ( sint ))`

`=> f'(t) = 2tsint + t^2 cost`