How do you find the derivative of #f(x)=-2x^-3+x^2-7#?

2 Answers
Jul 29, 2018

#f'(x)=6x^-4+2x#

Explanation:

Use the power rule for differentiation:

We know that the derivative of #x^n# is #nx^(n-1)#.

The function #f(x)=-2x^(-3)+x^2-7# has three parts.

We apply the power rule on each part.

#color(red)(Part-1#: #-2x^-3#
Derivative: #-2(-3)x^((-3-1))#
Derivative: #color(red)(6x^-4#

#color(blue)(Part-2#: #x^2#
Derivative: #(2)x^((2-1))#
Derivative: #color(blue)(2x#

#color(green)(Part-3#: #7#
The derivative of a constant is zero, so:
Derivative: #color(green)(0#

We add the derivatives of each part up:

#color(red)(6x^-4)+color(blue)(2x)+color(green)(0)#

So the derivative would be:

#f'(x)=6x^-4+2x#

Jul 29, 2018

#6x^(-4)+2x#

Explanation:

Since we're dealing with a polynomial, we can find the derivative with the help of the Power Rule.

We simply multiply the exponent by the coefficient, and decrement the power by one. Recall that the derivative of a constant is zero.

We now have:

#6x^(-4)+2x#

Hope this helps!