Question

How do you find the derivative of the function `f(x)=1.5x^2-x+3.7`?

Answer 1

`f'(x)=3x-1`

Explanation:

the rule for polynomials for differentiation is;

`y=ax^n=>f'(x)=anx^(n-1)`

`f(x)=1.5x^2-x+3.7`

`f'(x)=2xx1.5x^(2-1)-1xxx^(1-1)+0`

A constant differentiated gives `0`

`:.f'(x)=3x-1`