How do you find the derivative of the function $f (x) = - 2 x^{- 3} + x^{2} - 7$ $f(x)=-2x^-3+x^2-7$ ?

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How do you find the derivative of the function $f (x) = - 2 x^{- 3} + x^{2} - 7$ $f(x)=-2x^-3+x^2-7$ ?

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Answer 1 · 2016-02-02T21:23:20

$6 x^{- 4} + 2 x$ $6x^-4 + 2x$

Explanation:

using the 'power rule'

If f(x $) = a x^{n}$ $) = ax^n$

then $f'(x) = nax^(n-1)$

this is then applied to each term in the function.

$f'(x) = (-3)(-2)x^-4 + 2.1 x+ 0$

( the derivative of a constant term is 0 )

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How do you find the derivative of the function $f (x) = - 2 x^{- 3} + x^{2} - 7$ $f(x)=-2x^-3+x^2-7$ ?

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Explanation:

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How do you find the derivative of the function f(x)=-2x^-3+x^2-7f(x)=−2x−3+x2−7f(x)=-2x^-3+x^2-7?

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How do you find the derivative of the function $f (x) = - 2 x^{- 3} + x^{2} - 7$ $f(x)=-2x^-3+x^2-7$ ?