How do you find the derivative of $y = \frac{1}{x^{8}}$ $y=1/x^8$ ?

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Answer 1 · 2016-12-06T00:12:09

Rewrite it as $y = x^{- 8}$ $y=x^(-8)$

$y = \frac{1}{x^{8}} = x^{- 8}$ $y = 1/x^8 = x^-8$

Not use the power rule to see that

$y' = -8x^-9 = -8/x^9$

How do you find the derivative of y=1/x^8y=1x8y=1/x^8?