How do you find the derivative of #y=1/x^8#? Calculus Basic Differentiation Rules Power Rule 1 Answer Jim H Dec 6, 2016 Rewrite it as #y=x^(-8)# Explanation: #y = 1/x^8 = x^-8# Not use the power rule to see that #y' = -8x^-9 = -8/x^9# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 2187 views around the world You can reuse this answer Creative Commons License