How do you find the domain and range for $f(x) = 1/(1+x^2)$ ?

Question

1575 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-09T21:47:31

Domain: $RR$

Range: $0<x≤1$

The domain of the function is all of $RR$ as no value of $x$ causes the function to be undefined.

The range is $0<x≤1$ . For $x=0$ the function takes the value $1$ and for all $x→±∞$ the function is decreasing and tends to $0$ .

How do you find the domain and range for f(x) = 1/(1+x^2)f(x) = 1/(1+x^2)?