Question

How do you find the domain and range for `f(x)=sqrt(4-2x)`?

Answer 1

`(-oo,2]`

Explanation:

You may know that the content in a square route should be equal to or more than 0.
So, first we suppose that: `4-2x>=0`
`4-2x>=0`
`4>=2x`
`2>=x`
`x<=2`
`(-oo,2]`
so the x can take values from 2 and less than 2 ,for example: 1,0,...,`-oo`