How do you find the domain and range of 1/(x-7)1x7?

1 Answer
Apr 12, 2017

x inRR,x!=7
y inRR,y!=0

Explanation:

"let " y=1/(x-7)

The denominator of y cannot equal zero as tis would make y undefined. Equating the denominator to zero and solving gives the value that x cannot be.

"solve " x-7=0rArrx=7larrcolor(red)" excluded value"

rArr" domain is " x inRR,x!=7

"Rearrange the function to make x the subject"

rArry(x-7)=1

rArrxy-7y=1

rArrxy=1+7y

rArrx=(1+7y)/y

rArry=0larrcolor(red)" is the excluded value"

rArr"range is " y inRR,y!=0