How do you find the domain and range of f(x)= (2x^2+7x-15) / (x+5)f(x)=2x2+7x−15x+5?
1 Answer
May 17, 2018
Explanation:
"factorise and simplify by cancelling"
f(x)=((2x-3)cancel((x+5)))/cancel(x+5)=2x-3
f(x)" simplifies to a linear expression which has no "
"restrictions on it's domain and hence no restrictions"
"on it's range"
rArr"domain "x inRR
rArr"range "y inRR
graph{(2x^2+7x-15)/(x+5) [-10, 10, -5, 5]}