How do you find the domain and range of f(x)= (2x^2+7x-15) / (x+5)f(x)=2x2+7x15x+5?

1 Answer
May 17, 2018

x inRR,y inRR

Explanation:

"factorise and simplify by cancelling"

f(x)=((2x-3)cancel((x+5)))/cancel(x+5)=2x-3

f(x)" simplifies to a linear expression which has no "
"restrictions on it's domain and hence no restrictions"
"on it's range"

rArr"domain "x inRR

rArr"range "y inRR
graph{(2x^2+7x-15)/(x+5) [-10, 10, -5, 5]}