How do you find the domain and range of $f (x) = \sqrt{I n x}$ $f(x) = sqrt{Inx}$ ?

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Answer 1 · 2017-01-22T14:51:31

There is no x-intercept. Range $: f > 0$ $:f > 0$ . Domain : $x > 1$ $x > 1$ . See the illustrative graph.

To make f real, $x > 1$ $x > 1$ .

As $x \to 1_{+}, f \to 0$ $x to 1_+, f to 0$ and as $x \to \infty, y \to \infty$ $x to oo, y to oo$ .

graph{sqrt( ln x) [-10, 10, -5, 5]}

How do you find the domain and range of f(x)=√Inxf(x) = sqrt{Inx}?