How do you find the domain and range of f(x) = x^2+3?
1 Answer
Jun 22, 2018
Explanation:
f(x)=x^2+3" is defined for all real values of x"
"domain is "x inRR
(-oo,oo)larrcolor(blue)"in interval notation"
"the vertex of "x^2+3" is "(0,3)
"since "a>0" it is a minimum turning point " uuu
"range is "[3,oo)
graph{x^2+3 [-10, 10, -5, 5]}