How do you find the domain and range of f(x) = x^2+3?

1 Answer
Jun 22, 2018

x inRR,y in[3,oo)

Explanation:

f(x)=x^2+3" is defined for all real values of x"

"domain is "x inRR

(-oo,oo)larrcolor(blue)"in interval notation"

"the vertex of "x^2+3" is "(0,3)

"since "a>0" it is a minimum turning point " uuu

"range is "[3,oo)
graph{x^2+3 [-10, 10, -5, 5]}