How do you find the domain and range of $f(x) = (x)/(sqrt{x - 4})$ ?

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Answer 1 · 2018-06-17T15:57:17

$x>4$ and #y>=4

Since we have a square root in the denominator we get

$x>4$

for

$x/sqrt(x-4)$ we get

$x/sqrt(x-4)>=4$
this is true, since we get

$(x-4)^2>=0$

How do you find the domain and range of f(x) = (x)/(sqrt{x - 4})f(x) = (x)/(sqrt{x - 4})?