How do you find the domain and range of $g(x) = -11/(4 + x)$ ?

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Answer 1 · 2018-07-17T07:52:10

The domain is $x in (-oo,4)uu(4,+oo)$ . The range is $y in (-oo,0)uu(0,+oo)$

The function is

$f(x)=-11/(4+x)$

The denominator must be $!=0$

Therefore,

$4+x!=0$

$x!=-4$

The domain is $x in (-oo,4)uu(4,+oo)$

To find the domain, Let

$y=-11/(4+x)$

$y(4+x)=-11$

$yx+4y=-11$

$yx=-11-4y$

$x=(-11-4y)/y$

The denominator must be $!=0$

$y!=0$

The range is $y in (-oo,0)uu(0,+oo)$

graph{-11/(4+x) [-33.13, 18.18, -13.24, 12.43]}

How do you find the domain and range of g(x) = -11/(4 + x)g(x) = -11/(4 + x)?