How do you find the domain and range of $h (t) = \frac{1}{t^{2}}$ $h(t) = 1/(t^2)$ ?

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Answer 1 · 2017-05-17T23:47:10

See below.

The domain of a function relates to its $x$ $x$ value, or in this case, $t$ $t$ . The range is the function, or $h (t)$ $h(t)$ .

$\frac{1}{0}$ $1/0$ is undefined, which happens when $t = 0$ $t=0$ , so the domain does not include zero.

Since the denominator is squared, the range of the function will never be negative.

As $t$ $t$ approaches infinity, $h (t)$ $h(t)$ approaches $0$ $0$ .
As $t$ $t$ approaches zero, $h (t)$ $h(t)$ also approaches $\infty$ $oo$ .

Thus, the domain is $(\infty, 0) \cup (0, \infty)$ $(oo,0)uu(0,oo)$ , and the range is $(0, \infty)$ $(0,oo)$ .

How do you find the domain and range of h(t) = 1/(t^2)h(t)=1t2h(t) = 1/(t^2)?