How do you find the domain and range of $h(x)= 1/(x+1)$ ?

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Answer 1 · 2017-03-29T11:11:38

Domain is $RR , x != -1$
Rage is $RR , h(x) != 0$

$h(x) = 1/(x+1)$
Domain: Denominator must not be $0 :. x+1 != 0 or x != -1$
Domain is any real value except $-1$
So Domain is $RR , x != -1$

Range is any real value except $0$
So Rage is $RR , h(x) != 0$ graph{1/(x+1) [-10, 10, -5, 5]}[Ans]

How do you find the domain and range of h(x)= 1/(x+1)h(x)= 1/(x+1)?