How do you find the domain and range of $h(x)= x^2 - 5$ ?

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Answer 1 · 2015-07-23T03:01:56

Domain : $x$ may have any value

Range:Since $x^2$ is always $>=0$ the function will always be $>=-5$ .
There is no upper limit.

So:
Domain: $-oo < x<+oo$
Range $-5<=h(x)<+oo$

How do you find the domain and range of h(x)= x^2 - 5h(x)= x^2 - 5?