How do you find the domain and range of $root4(9-x^2)$ ?

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Answer 1 · 2017-08-01T11:08:47

Domain : $-3 <= x <= 3$ or $[-3, 3]$
Range: $0 <= f(x) <= sqrt3 or [0,sqrt3]$

$f(x)=root(4) (9-x^2)$ . For domain under root must be $>=0$

$:. 9-x^2 >= 0 or x^2 <= 9 :. x <= 3 or x>= -3$

Domain : $-3 <= x <= 3$ or $[-3, 3]$

Range : Minimum value : $f(x)=0$ when $x = +-3$ and

maximum value : $f(x)=sqrt ((sqrt (9) ) )= sqrt 3$ when $x = 0$

Range: $0 <= f(x) <= sqrt3 or [0,sqrt3]$

graph{(9-x^2)^0.25 [-10, 10, -5, 5]} [Ans]

How do you find the domain and range of root4(9-x^2)root4(9-x^2)?