Let g(x)=sqrt(25-(x-2)^2)+3g(x)=√25−(x−2)2+3
What is under the sqrt√ sign is >=0≥0. this is the domain
So,
25-(x-2)^2>=025−(x−2)2≥0
25-(x^2-4x+4)>=025−(x2−4x+4)≥0
x^2-4x+4-25<=0x2−4x+4−25≤0
x^2-4x-21<=0x2−4x−21≤0
Let's factorise
(x-7)(x+3)<=0(x−7)(x+3)≤0
Let f(x)=(x-7)(x+3)f(x)=(x−7)(x+3)
Let 's do a sign chart to solve this inequality
color(white)(aaaa)aaaaxxcolor(white)(aaaa)aaaa-oo−∞color(white)(aaaa)aaaa-3−3color(white)(aaaa)aaaa77color(white)(aaaa)aaaa+oo+∞
color(white)(aaaa)aaaax+3x+3color(white)(aaaaa)aaaaa-−color(white)(aaaa)aaaa++color(white)(aaaa)aaaa-−
color(white)(aaaa)aaaax-7x−7color(white)(aaaaa)aaaaa-−color(white)(aaaa)aaaa-−color(white)(aaaa)aaaa-−
color(white)(aaaa)aaaaf(x)f(x)color(white)(aaaaaa)aaaaaa++color(white)(aaaa)aaaa-−color(white)(aaaa)aaaa++
Therefore,
f(x)<=0f(x)≤0 when x in [-3,7]x∈[−3,7], this is the domain
To calculate the range,
When x=-3x=−3, =>⇒, g(-3)=3g(−3)=3
When x=7x=7, =>⇒, g(7)=3g(7)=3
When x=2x=2, =>⇒, g(2)=8g(2)=8
Let y=sqrt(25-(x-2)^2)+3y=√25−(x−2)2+3
The range is y in [3,8]y∈[3,8]
graph{(sqrt(25-(x-2)^2)+3) [-9.74, 12.76, -2.055, 9.195]}