How do you find the domain and range of sqrt (4-5x)?

1 Answer
Mar 18, 2016

I found:

-oo<x<=4/5
0<=y<+oo

Explanation:

The domain is found setting the argument of the square root bigger or equal to zero (to avoid a negative root):
4-5x>=0
so that must be: x<=4/5
The domain will be all the x from -oo up to and comprising 4/5.

The range will be all the y that go from zero (when x=4/5) up to +oo.

Graphically:

graph{sqrt(4-5x) [-10, 10, -5, 5]}