How do you find the domain and range of $\sqrt{8 - x}$ $sqrt(8-x)$ ?

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Answer 1 · 2017-03-02T05:21:19

Domain : $x \in (- \infty, 8)$ $x in (-oo , 8)$
Range : $y \in (0, \infty)$ $y in (0, oo)$

For Domain,

$8 - x \geq 0$ $8-x >=0$

$x \leq 8$ $x<=8$

Domain : $x \in (- \infty, 8)$ $x in (-oo , 8)$

For Range,

$y = \sqrt{8 - x}$ $y= sqrt(8-x)$

Range : $y \in (0, \infty)$ $y in (0, oo)$

How do you find the domain and range of √8−xsqrt(8-x)?